How many grams of Ce(IO3)4 will dissolve in 100mL of water?

Ce(IO₃)₄ is a compound that is not frequently referenced in literature. A study shows experimental measurements of solubility ranging from 2.72 - 2.88 mol/dm³.

Using these solubility values, the expected amount of Ce(IO₃)₄ that could be dissolved in 100mL of water is 0.272 - 0.288 moles. Converting moles of Ce(IO₃)₄ is possible by multiplying the amount of moles by the molecular weight of 839.7 g/mol to get an answer of 228.4 - 241.8 g.

Due to the lack of supporting literature, we are supplying calculations using a more readily referenced compound, Ce(IO4)₄. The solubility of cerium periodate, Ce(IO₄)₄, is 0.015 g/mL of water at 25°C. So, if there is 100 mL of water present, then the answer is 1.5 grams that can be dissolved.

This is how you find the answer: Solubility in terms of g/mL times the amount of solvent in terms of mL equals the amount of chemical that can be dissolved, in terms of grams.

Be careful when reading solubility values because they are given in various units depending on the source. Some unit conversion may be required to have a value that is useful to solving your problem!

Chemistry has a reputation as a hard science to master, yet if you follow simple steps, it's not that bad. Here are some homework and study tips to help you shared by Thoughtco.com.

Tag: water