How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH4NO3 in order to prepare a 0.452 m solution?

769 grams is needed. V=m/M/c --> V=27.8 g / 80 g/mol / 0.452 mol/L = 0.769 L as water has a ...more?
Updated on Wednesday, February 01 2012 at 10:57AM EST
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